Question

You have been given the task of finding out what proportion of students that enroll in a local university actually complete their degree. You have access to first year enrolment records and you decide to randomly sample 110 of those records. You find that 89 of those sampled went on to complete their degree. a) Calculate the proportion of sampled students that complete their degree. Give your answer as a decimal to 3 decimal places. Sample proportion = You decide to construct a 95% confidence interval for the proportion of all enrolling students at the university that complete their degree. If you use your answer to part a) in the following calculations, use the rounded version. b) Calculate the lower bound for the confidence interval. Give your answer as a decimal to 3 decimal places. Lower bound for confidence interval = c) Calculate the upper bound for the confidence interval. Give your answer as a decimal to 3 decimal places. Upper bound for confidence interval =

Answer 1

here sample size is llo n-llo hero X = number of thowho has wont on 6 to completo theio degree. x=69 The sample proportion is A p = a ) p=4 p=89 110 - 0.8 809 b) То construed construct g 5% confidence intorual of proportion hest (1-4) 100% of Ci I. of praportion is ( p - 2012 Spa p + Z212 JP%) n L = 0.05 The low or bound of confidence intorval is Þ - 2212 Jpg p=o.log q=1-D FI-0809 0-19) = 20.0512=1.96 o rog - lig6 6.80986-191 110 CSScanned with CamScanner

The low or bound of confidence intervalis= 07355 =0*736 c) The upper bound of confidence interval is = b + 7212 Spa o. 8o9 t 1.96 o 8o9x8.lg llo 0.882 CSscanned with CamScanner