9)
........
10)
..........
11)
a)
Number of Items of Interest, x =
82
Sample Size, n = 116
Sample Proportion , p̂ = x/n = 0.707
..........
b)
z -value = Zα/2 =
1.960 [excel formula =NORMSINV(α/2)]
Standard Error , SE = √[p̂(1-p̂)/n] =
0.042263
margin of error , E = Z*SE = 1.960
* 0.04226 = 0.0828
Interval Lower Limit = p̂ - E =
0.70690 - 0.08283 =
0.624
c)
Interval Upper Limit = p̂ + E =
0.70690 + 0.08283 =
0.790
.............
Please let me know in case of any doubt.
Thanks in advance!
Please upvote!
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