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Young’s Experiment is performed with wavelength 420nm and the slits are 2mm apart. How far away...

Young’s Experiment is performed with wavelength 420nm and the slits are 2mm apart. How far away should you place a screen (in m) so that the closest fringes are 2mm apart?

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ya Si Screen Given Y= 2mm L-? wavelength λ= 420nm and silts d= 2mm We know that Y= L/d Hence L= y*d/ λ = (2*2*10-6)/420*10^-9

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