Question

Refer to diagram 4. Before solving, please convert 18.4 g to kg!!! and please put the final answer to 3 significant figures thank you so much!

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A pendulum consists of point mass 18.4 g on the end of a 0.425 m massless string. The mass is pulled aside so the string makes an angle θ = 36o with the vertical (as shown) and released with initial speed vo = 3.82 m/s downward (but perpendicular to the string). Assume there is no friction anywhere, and the mass keeps the string taut so the velocity of the mass is always perpendicular to the string. Find the tension, in N, in the string as the mass passes through its lowest point.

Answer 1

Speed at the bottom is given by

Vo = Vv6+2gh

Where $v_{0}$ =3.82m/s is the initial speed and h is the initial height from bottom given by,

h=1-lcost = 11 - cos)

So tension at the bottom can be given as,

T=mg+ more m[v+2gl (1 – cos) + = m(* + 9(3 – 2c080)] 3.822 0184 +9.8(3 – 2cos36') 10.425 + 9.873 = 0.881 N