Calculate the ATP equivalens from complete oxidation of 15 moles of 20:0
Number
of Carbons Common Name Systematic Name Symbol Structure
20 Arachidic acid Eicosanoic acid 20:0
CH3(CH2)18COOH
Step 1.-
Number of Carbons/2 = Number of Acetyl CoA formed.\
=20/2 =10 Acetyl CoA
Step 2.:
= [(n/2)-1]
== [(10/2)-1] =9 rounds
Step 3 (Option a):
(9 x 4) + (10 x 10)
step 4 = -2-----------------activation of fatty acid
Total: 134 ATP-------------------for one mole
15 moles x 134 ATP= 2010 ATP -------ANSWER
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