A precipitate forms when a solution that is 0.10 M in Cu2+, Pb2+, and Ni2+ is...
A precipitate forms when a solution that is 0.10 M in Cu2+, Pb2+, and Ni2+ is saturated with H2S and adjusted to pH = 1. What sulfides are present in the precipitate?
[H2S] = 0.10 M; for H2S, Ka1 ´ Ka2 = 1.1 ´ 10–24
Ksp: CuS = 8.5 ´ 10–45, PbS = 7.0 ´ 10–29, NiS = 3.0 ´ 10–21
(The answer is D, Could anyone explain it by steps?)
|
A) |
CuS, PbS, and NiS |
|
B) |
PbS and NiS |
|
C) |
NiS |
|
D) |
CuS and PbS |
|
E) |
CuS |
Homework Answers
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A precipitate forms when a solution that is 0.10 M in
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please solve and show work!
A solution of 0.10 M (each) Ni2+ and Cu2+ are separated using selective precipitation by the addition of solid Na2CO3. Assuming no volume change upon this addition, how much of the first precipitated ion remains at the point where the second ion begins to precipitate? Ksp of NiCO3 = 1.4'10-7 Ksp of CuCO3 = 2.510-10 A. 1.4 x 10-6 M CUCO3 B. 1.2 x 102 M CUCO3 C. 1.8x 10-4M NICO D. 1.4 x 106...
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