With the switch open, roughly what must be the resistance of theresistor on the right...
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be the same as when the switch is closed (and the resistances of the two resistors are 20 and 10Ω
| 5 Ω | |
| 30 Ω | |
| 15 Ω | |
| 7 Ω |
Homework Answers
\(\frac{1}{R_{\text {parallel }}}=\frac{1}{R_{\mathrm{t}}}+\frac{1}{R_{2}}=\frac{1}{10}+\frac{1}{20} \Rightarrow R_{\text {parallel }}=7 \Omega\)
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With the switch open, roughly what must be the resistance of theresistor on the right...
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