What is the direction of the acceleration of the block when it is at the point...

Question

Question

What is the direction of the acceleration of the block when it is at the point 0.35 m,y 0.65 m?

Answer 1

Answer #1

Solution,

On Differentiating wrt to x and y,

Fx = 2 x 5.75 x

Fy = - 3 x 3.75y^2

At point (0.35, 0.65)

Acceleration, ax = 2 x 5.75 x 0.35/0.04 = 100.63 m/s^2

Acceleration, ay = - 3 x 3.75 x 0.65^2/0.04 = - 118.83 m/s^2

Magnitude = sqrt(ax^2 + ay^2) = 155.71 m/s^2

Direction, theta = arctan (ay/ax) = 49.74 degree

So, theta = 360 - 49.74 = 310.26 degree

Comment in case any doubt please rate my answer ....

Answer 2

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