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A 69-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she...

A 69-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.5 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
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Using Conservation of Energy principle we can solve this. = Tatale Energy at Bar Total Energy at altitude, h. Initially suppo. h = [v,? - v? 2 g ginen, V = 11 m/s V2 = 1.5 m/s g vé acceleration due to grauity, its value is g= 9,8 mys? (117² - (105)2

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