Question

please answer only if you know

show all work

subject is calculus 1

(2) Find the equation of the tangent line to the curve 3y + 2x2 = x?y2 + 4 at (1,2). (6 points)

Answer 1

the curve m= 2 > dy tyx = वर Soth we have to find equation of tangend line to By tef=alyety - at clie] let due is the slope of tangend line ol (112). Then equation of tangent line passing through (112) is given by ly_2= m(x-1) How differentating (i), worit, as we get d (by tex] = h (2²y +4) ted (12²) de laye) + 2 hely) gyz-y + 3xy to du har (3-Dy) day2-4a dy axlye ol 3-gyke elow slope of tangent ad (1, 2) is given by dy 9.0 (4-9) 3-2.13.1 녹 4 Hence equation of tangend line from liig y-2=-4 (0-4) 0 > de m da > m=-4 m y = -uxto Best of luck