Question

For Prob 9.5 9.47 In the circuit of Fig 9.54, determine the value of i,Cr If V.-8/30" V in the circuit of Fig. 959. find l," 9.52 2miH ら(n20 115 cos 2,000, v C Figure 9.59 For Prob. 9.52 Figure 9.54 For Prob. 9.47 9.53 Find I, in the circuit of Fig. 9.60 9.48 Given that v,(,) = 20 sin( 100,-40") in Fig. 9,55. determine i,) 4Ω ML 10 Ω 3052 , tn) ( 10Ω 160 430 V 8Ω Figure 9.55 For Prob. 9.48 Figure 9.60 For Prob. 9.53 9.49 Find v, () in the circuit of Fig. 9.56 if the current i, 9,54 In the circuit of Fig. 9.61, find V, if - 30/0 A. through the 1-22 resistor is 8 sin 200r A 岛# 2Ω 152 20 j452 Figure 9.61 For Prob 9.54 Figure 9.56 For Prob. 9.49

Answer 1

Sol 20 cos 2000 t = 20 angle 0 degree w = 2000 t rad/sec 2 m H = j w L = j (2000) times 2 times 10^-3 = j 4 ohm 50 mu F = 1/j w c 50 mu F = 1/j(2000) (50 times 10^6) implies - j 10 ohm frequency domain equivalent circuit is z_in = 2 + - j 10 (20 + j 4)/ - j 10 + 20 + j 4 z_in = 2 + 40 - j 200/20 - j 6 z_in = 2 + 4.588 - j 8.626 = 6.588 - j 8,.626 z_in = 10.854 angle - 52.63 degree I_s = v_s/z_in = 5/10.854 angle - 52.63 degree = 0.4607 angle 52.63 degree i s(t) = 4607 cos (2000 t + 52.63 degree) A v_s(t) = 20 sin (200 t - 40 degree) =: w = 100 0.2 H = J w LL = j(100) (0.2) = j 20 ohm 0.5 m F = 1/j w c = 1/j(100) (0.5) times 10^-3 = -j 20 ohm v_s(t) = 20 sin (100 t - 40 degree) v_s(t) = 20 angle - 40 degree) v_1 - 20 angle - 40 degree/10 + v_1 - 0/j 20 + v_1 - 0/30 - j 20 = 0