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The figure shows an arrangement of four charged particles, with angle θ = 33.0 ˚ and distance d = 2.00 cm. Particle 2 has charge q2 = 6.40 × 10-19 C; particles 3 and 4 have charges q3 = q4 = -4.80 × 10-19 C. (a) What is the distance D between the origin and particle 2 if the net electrostatic force on particle 1 due to the other particles is zero? (b) If particles 3 and 4 were moved closer to the x axis but maintained their symmetry about that axis, would the required value of D be greater than, less than, or the same as in part (a)?

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Answer #1

EA= EB - 2 - = 2.38 cm CoS 33° AO =B0 = 2:38 Sin 33° = 129 cm. 92 = a ye, q3=2y = -3e Ee=k(4e) ; Ea=E6=-kie (2+ D2 2.382 Eax

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