Question

Suppose a 500. mL flask is filled with 1.3 mol of H2 and 0.10 mol of HC1. The following reaction becomes possible: H2(g) + Cl2(g)-2HCl (g) The equilibrium constant K for this reaction is 3.03 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.

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Answer #1

If the flask is filled with H2 and HCl the reaction Given in the question cannot proceed.

But if H2 and Cl2 is taken in the flask the above reaction can occur. Hence the concentration given for HCl taken in the flask is taken as concentration of Cl2 and the following calculaion is done.Kc 3.03. 303 (1.3-X)(0.10x) Changt 3.03 ( 1.3-z) (0.101) 2. da a 0.91b: 4.4 cC0.3939) o 4,24ty(4,24)ユー4(0.99)(-0.3939) χ , 0.1814mol of HCl is produced.

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