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Suppose a 250. ml flask is filled with 1.5 mol of Cl, and 1.3 mol of HCl. The following reaction becomes possible: H2(g) + Cl

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Гц, 1 = 1.5 = см Гна) - 3 - 5.2м О, то 0,2SD Now, 1 t 2Hce 5,2 - 2х 5.2 -27 ctx Ex tx + 6 (5.2 -2x) o.so x (67) - Т. 347 14 м

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