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1. In the following problem, mass of the roller is 100 kg, a couple moment of 50N-m is applied on the wheel and external forc

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I M=50 kw.m F=5N / Mim (T) 91 Tasque = ID I-moment of imesta da angul as acceleisatien ::T? FX0.5 + 50 + (ong )*0.2 ruse staBere accelasetion a F - alls cong) = ma 5 -0.2 x 100x10 = ma 5 - 200 = ma hese static friction will be 5 upto force f Soi 57.: 0= wol + bat? 30 + 4x31164452 0 = 39.55 staal So, 2a (Sadian) = 274 (distance) 39.55 (sadion) →? = 39.55% 208 2A = 39.55 x

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