Question

In need this in C language!

Write a program that declares a 40 element array of type double. Initialize the array so that:

the first 10 elements are equal to the square of the index variable

the next 10 each elements is equal to three times the index variable

the next 10 each element is equal to the sum of an element in the first 10 + an element in the second 10

the last 10 each element is equal to 10 * an element in previous 10

Output the array so that 10 elements per line are printed

The output should look like:

    
81 57 33 144 351 672 1125 1728 249934564617 0 330 1440 3510 6720 11250 17280 24990 34560 46170 16 49 25 45 64 54 36 30 36 39 42 4 8 51

Answer 1

#include<stdio.h>
int main()
{
int arr[40];
int i;
for( i=0;i<10;i++)
{
arr[i]=i*i;
}
for( i=10;i<20;i++)
{
arr[i]=i*3;
}
for(i=20;i<30;i++)
{
arr[i]=arr[i-20]*arr[i-10];
}
for( i=30;i<40;i++)
{
arr[i]=arr[i-10]*10;
}
//printing element of array
for(i=0;i<40;i++)
{
if(i%10==0)
printf("\n");
printf("%6d\t",arr[i]);

}
}