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Go Tools Bookmarks Window Help hw03.pdf (page 1 of 2) 2. Exercise 3-28. Thethickness measurement fo a wall of plastic tubing, in millimeters, varies according to a cumulative distribution function (cdf) x < 2.0050 F(x) = 200x-401 2.0050 2.0100 x x>2.0100 Determine the following. (a) P(X s 2.0080) (b) P(X> 2.0055) (c) If the specification for the tubing requires that the thickness measurement be between 2.0090 and 2.0100 millimeters, what is the probability that a single measurement will indicate conformance to the specification? Tip: Express each probability in terms of the cdf F(x), then evaluate.
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Function CCDF 乂く2.OOSD P Cx 2.oooF C2.00o = 10.6 PC X2.00 SS) FC2. OuSs) -2 00O - L 200 2. OOTS) - 41 1 L 401.1401e e, ve to determine -20 (2.0090

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