Please draw out structure and label spectra
Please draw out structure and label spectra NaoH HA H2O CH3 Ketone Aldehyde Adol condensation product...
Match the starting ketone or aldehyde with appropriate product of either aldol addition or adol condensation reaction. A ketone or an aldehyde from the list undergo either aldol addition (in a case aldol addition product can not undergo further elimination) or aldol condensation reaction in protic solvent under basic catalysis. Match the starting ketone or aldehyde with appropriate product of either aldol addition or aldol condensation reaction propanal acetaldehyde 2-ethyl-2-hydroxy-hexanal 2-methylbuta ethanal Please answer 2-ethyl-4-methyl 2-hexenal Choose 2-methyl-2-pentenal 2-ethyl-3-hydroxy-2,4-dimethyl hexanal...
Which adol condensation product will the following combinations of starting materials form? 2. CH3 H3C 3. 4. 5. CH H C CH3 6.
Please fill out charts:) Determine the structure of the ketone with molecular formula C_6H_12O giving the^1H NMR below and finish the table Draw the structure of the molecular fragment that corresponds to the given^1H NMR data 2 points. [1H] no net at 1.3 ppm [2H] quartet at 2.1 ppm
Please analyze the IR and NMR spectra. The product is N,N-diethyl-m-toluamide. The product is obtained by the following reactions Please label all major peaks. Solvent is Et2O. Extracted with NaOH and then HCl and then H2O. Dried and then evaporated. To further purify, hexane was used in column chromatography to elute the product. Then evaporated. CH3 CH3 SOCI2 + SO2 O=0 ОН CH3 CH3 -- + excess (CH3CH2)2NH + (CH3CH2)2NH2* crt ether CI 'N-CH2CH3 CH,CHE 1000 11 100 100 100...
Below is the 1H-NMR of the starting material. Draw the structure of the product on the 1H-NMR spectra and pencil in the changes you would expect to see in the spectra. Be sure to include multiplicity where applicable. Attach the spectra to your reflection. Product is 2-butoxynapthelene aromatic H (7) OH (1) PPM
Analysis Questions 1. Given the structure of an aldehyde and a ketone, predict the structure of the reaction product. Use the table below to practice and to predict the possible products your class synthesized. HẠC CHỊ acetone cyclopentanone benzaldehyde Product #1, m.p. 113 °C Product #2, m.p. 189 °C NA trans-cinnamaldehyde Product #3, m.p. 144 °C 2. Include the IR spectrum of your product. Label important peaks with corresponding functional group. 3. Include the melting point your product. 4. Draw...
Molecule C: Molecule D: Can someone PLEASE EXPLAIN the answers?????? 2. Below are the 'H and 13C NMR spectra for four isomers of C&H:02. Provide the structure that produced each set of spectra. Molecule A: 'H NMR 3H 3H no coupling, so no adjacent carbons with hydrogen atoms 2H 5 3 2 0 PPM 13C NMR aldehyde or ketone no aldehyde in 1H NMR, SO ketone 220 200 180 160 140 120 100 PPM 80 60 40 20 0 Molecule...
Draw the structure of the aldehyde or ketone and the Grignard reagent that will react to form the following compound: CH3 Н3С. ГОН • You do not have to consider stereochemistry • In cases where there is more than one answer, just give one. • Draw the Grignard reagent as a covalent magnesium bromide. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right comer. • Separate multiple reactants using the + sign...
Given the structure of an aldehyde and a ketone, predict the structure of the reaction product Use the table below to practice and to predict the possible products your class synthesized. 1. CHз Hас cyclopentanone acetone н benzaldehyde Product #1, m.p. 113 °C Product #2, m.p. 189 °C н о н н trans-cinnamaldehyde Product #3, m.p. 144 °C NA
Label the spectra and propose a structure for the compound. The IR spectra are listed in the translation. Compound 2 R Spectrum Medisch 3400 1720 4000 3000 1600 vomi) 1200 183 Mass Spectrum So base UV Spectrum mas 253 nm 109,9€ 2.6) homas 250 nm 109,96 2.7) ho mar 284 m 109,0 2.5) M -220N) CH2O| 280 40 80 120 160 200 240 13C NMR Spectrum (100 . CDC, DEPT CH CH CH protondeco 200 160 1 20 80 400...