Question

The following details the results of a serial dilution of E. coli: Effective Dilution Factor on...

The following details the results of a serial dilution of E. coli:

Effective Dilution Factor on Plate CFUs
105 1095
106 178
107 5
108 None

The "effective dilution factor on plate" already takes into account

the fact that you plated 0.1 ml of the dilution.

How many CFUs/ml were present in the original sample?

a. 1.78 x 10^8
b. 1.14 x 10^8
c. 1.125 x 10^8
d. 1.095 x 10^8
0 0
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Answer #1

CFU/ml in the original sample = (no. of colonies x di;ution factor) / volume of culture plate

= (1095 x 104) / 0.1

= 1.095 x 108 CFU/ ml

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