The following details the results of a serial dilution of E. coli:
Effective Dilution Factor on Plate | CFUs |
105 | 1095 |
106 | 178 |
107 | 5 |
108 | None |
The "effective dilution factor on plate" already takes into account
the fact that you plated 0.1 ml of the dilution.
How many CFUs/ml were present in the original sample?
a. | 1.78 x 10^8 |
b. | 1.14 x 10^8 |
c. | 1.125 x 10^8 |
d. | 1.095 x 10^8 |
CFU/ml in the original sample = (no. of colonies x di;ution factor) / volume of culture plate
= (1095 x 104) / 0.1
= 1.095 x 108 CFU/ ml
The following details the results of a serial dilution of E. coli: Effective Dilution Factor on...
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