both A and B. is correct option.
Because, Force(F) = I × L × B
Where I is current and B is magnetic field(field strength), it shows that force exerted on current-carrying wire is directly proportional to current and field strength(magnetic field).
PLEASE UPVOTE
The force exerted on a current-carrying wire located in an external magnetic field is directly proportional...
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a) A wire carrying a current I is perpendicular to a magnetic field of strength B. Assuming a fixed length of wire, which of the following changes will result in decreasing the force on the wire by a factor of two? Select all correct answers - Decreas the current in th e wire to I/2 - Decrease the field strength to B/2 - Decrease the angle from 90 to 45 degrees - Decrease the angle form 90 to 30 degrees...
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(Magnetic Force on a Wire) A horizontal,
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(c) A negatively charged particle is moving to the right, directly above a wire having a current flowing to the right, as shown in the figure. In which direction is the magnetic force exerted on the particle? (d) A long straight conductor has a constant current I flowing to the right. A wire rectangle is situated above the wire, and also has a constant current I flowing through it (as shown). Draw the directions of the force and the torque that...
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The size of the magnetic force on a straight wire of length
L carrying current I in a uniform magnetic field
with strength B is
F=ILBsin(?).
Here ? is the angle between the direction of the
current (along the wire) and the direction of the magnetic field.
Hence Bsin(?) refers to the component of the
magnetic field that is perpendicular to the wire, B?. Thus
this equation can also be written as
F=ILB?.
The direction of the magnetic force on...