Question

(​Magnetic Force on a Wire​) A horizontal, current-carrying wire of mass m = 40.0 g is free to slide without friction along two vertical conducting rails spaced l = 80.0 cm apart as in Figure. A uniform magnetic field of B = 1.20 T is directed into the plane of the drawing. What magnitude and direction (to the right or to the left) must the current have if the force exerted by the magnetic field on the wire is just sufficient to balance the force of gravity on the wire? (Choose to the right as the positive direction and express the magnetic field by using the sign of the result with the proper   unit. That means if you get a result of a 9.22 and the direction of the field is to the right, just type 9.22 or if you find the direction of the field as to the left just type -9.22 with the proper unit in your answer.)

mi (Magnetic Force on a Wire) A horizontal, current-carrying wire of mass m 40.0 g is free to slide without friction along two vertical conducting rails spaced i = 80.0 cm apart as in Figure. A uniform magnetic field of B = 1.20 T is directed into the plane of the drawing. What magnitude and direction (to the right or to the left) must the current have if the force exerted by the magnetic field on the wire is just sufficient to balance the force of gravity on the wire? (Choose to the right as the positive direction and express the magnetic field by using the sign of the result with the proper unit. That means if you get a result of a 9.22 and the direction of the field is to the right, just type 9.22 or if you find the direction of the field as to the left just type -9.22 with the proper unit in your answer.) Answer: 0.409 A. Battery

Answer 1

a stro B node B dy Fone acting on the curent caning od placed in a magnetic field = 1B smo Here 0=90 :: Fg - IlB Chavitational fone or weight of the body F g м: Given these two forces balance IlB ng I = mg 4B 0.0 H0kg x 9.8 m/s2 0.80mx1.207 O.H09A gravitational fone is acting down, For should act upwards. So by Right hand mile curent is in right direction so tre.