Question

A passenger is running at his maximum velocity of 8 m/s to catch a train. When he is a distance d from the nearest entry to the train, the train starts from rest with a constant acceleration a= 1.0 m/s^2 away from him.

a. If d= 30 m and the passenger keeps running, will he be able to jump on the train?

b. What is the critical separation d_c such that the passenger just catches the train?

c. What is the speed of the train when the passenger catches it, assuming the critical separation d_c (explain)

d. What is the trains average speed for the time interval t=0 to the time when he catches it, assuming the critical separation d_c?

Answer 1

a) From kinematics we know, -(8) +2x1x 30 v-11.13 m/s As v >vhe passenger will be able to catch the train. b) The critical distance is the nearest distance from the passenger to entry the train So, the critical distance is d. -30m c) Let the final speed of the train is v v 2x1x30 so, the velocity of the train is lỵ-60m/s d) As, the train is moving with a constant acceleration, the avarage speed of the train will be 60m/s