Question

Please show all steps so I can understand it. Thanks

An aluminum spherical ball of radius 4 cm is charged with 5 PC of charge. A copper spherical shell of inner radius 6 cm and outer radius 8 cm surrounds it. A total charge of -8 uC is put on the copper shell. (a)Find the electric field at r = 3 cm. ON/C You are correct. Previous Tries Your receipt no. is 160-9388 (b)Find the electric field at r = 5 cm. -1.08*10^3 N/C Submit Answer Incorrect. Tries 9/100 Previous Tries (c)Find the electric field at r = 7 cm. -5.51*10^2 NC Submit Answer Incorrect. Tries 1/100 Previous Tries (d)Find the electric field at r = 9 cm. Submit Answer Tries 0/100

Answer 1

Ak a point lies inside the aluminium ball: We have a Conducting ball, so the charge will Spread out on the Surface of the Conductor which means that there will no electric field inside the ball Penc = 0 E =0 inside the aluminium Ak radius 0-3cm E = ON/ (point Shell)

5). Outside the At a point lies in the Space aluminium ball: The flux through the gaussian Surface is = E(41772) Gauss Law : $ = geda 0 gene E. E (4170) = Zenc Eo Renc 47772. E We know that 8.99x109 Nm? 4TTEO c² 8.99x109x5x10 (5x10 22 E = 1.798 x10? NIC

C. At a charge gaussias point lies inside the Copper Shell :- We have Conduct ucting Shell, so the total Inside the shell Surface is Zero Since the positive change sitive charge on the &nos sis face of the Aluminium rod induces an equal magnitud tude negative charge on the inner Surface of the Copper Shell, which means that there will be no eleckric field inside the Shell, in Genc = 0 At ge 7cm , Eleckric field E=ONIS

d. At a point lies in the space outsede aluminium ball bal! as well as Copper Shell Imagine a causs ean Surface with radius r. The charge enclosed by the gaussian Surface: Genc = 5x10 8x106 - 3x106c Yenc 4T8EO 9x109 x (-3x106) (9x10-272 € = 3.33x10CNIC