Question

A laser, pointed in the z direction, emits light in the form of a plane wave linearly polarised in the y direction. The equation for its electric field is

{\bf E}(x,y,z,t)={\bf E}_0\sin(kz-\omega t)

If the wavelength of the laser light is 4.8 nm, and the amplitude of its electric field wave is 4.8 N/C, what is the magnitude of the electric field (in N/C) at point (x,y,z)=(5.0,8.3,2.4) (all in nm) at time t=0?

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Answer #1


apply the relation between eelctric field angd magnetic field

as E = Bv

where v is speed

here v = speed of light = 3e8 m/s

\so


magnetic field B = E/v

B = 4.8 /(3e8)

B = 16 nm -----Answer

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