Question

A plane wave of frequency 900 MHz is and trave ling along -y direction with the electric field amplitude of 300 V/m (in vacuum). The value of electric field is -300 V at t=0 and y=0.

Choose a

magnetic field direction and define the polarization. Write the wave equation
of the electric and magnetic field.

Answer 1

300 Bo= Eo - KT w = c n radom Frequency of wave is f = 900x106 HZ i Angular frequency is w=294 >.w=20x900x106 rad's » w-5.6548668x109 rad/s Eo=3000/m fr Amplitude of electric field. Then, Bo= T +B=1067 3x108 Gamplitude of magnetic field. 5.6548668 X10 3x108 a 18.85 radni wave number. Direction of propagation of wave is my alis. Let magnetic field vibrates in X direction then electric field will Vébrates in Z direction such that Èx®) is along direction of propagation. Criven, at to, y=0, E=-3000/m=-80- .: If E= to sen(wt+ky +6) Then - Go=Eosin coto+6) k 2 2 send=48= 30 initial phase. Scanned' with CamScanner CS

1²=(Eosin (watt Ky+3. J+39)) (Bo sin Culttiky +30)) (-1) (: Rx (-1) = -9) Direction of palarisation is same as direction of vebration of electried field. .. Palarisation is along Zasis for chosesen directoon of magnetic field along x direction. The values of Eo, Bo, wand K is as cs calculated earlier. CamScanner