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4.10P) A plane wave of frequency 900 MHz is and travelling along -y direction with the electric field amplitude of 300 V/m (i

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8 ) sgiven frequency of plane ware = goo MHz OT = 9810 Hz The wave istrave ve istravelling along nyadirection so velocity of(ə) yo Tud x direction. Hence, we have E = 300 cos (xy + wet) =) < 300.cos (xy + 9710+)(-) Ym that unit vector of [l-ŷ) x t )4. e. Þa to -). Xe where Now the wave ) Xe = electroic susceptibility equation for electric & magnetic field are ( 22) & give2 o oo -0 0 2 u C² sy? share now cas leytnant) et 9) -x? cm (kyfwet) + cas lay twiet) ad cos (kytuet) 1-3 (9- *?) en (ny t we

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