PLEASE DO ALL QUESTIONS WITH WORK! T = KINETIC ENERGY
PLEASE DO ALL QUESTIONS WITH WORK! T = KINETIC ENERGY 2. In the lab a meganeutron...
8-14 positron-electron annihilation A positron et of mass m and kinetic energy K is annihilated on a target containing electrons e(same mass m) practically at rest in the laboratory frame: et(fast) +e-(at rest) → radiation a By considering the collision in the center-of- momentum frame (the frame of reference in which the total momentum of the initial particles is equal to zero), show that it is necessary for at least two gamma rays (rather than one) co result from the...
Problem 4 In a lab experiment, a cart of mass 2 kg, moving initially to the right at 3 m/s, collides head-on with a cart of unknown mass, moving initially to the left at 2 m/s. As a result of the collision, the carts bounce back with exactly the opposite velocity of what they had going in. Assume the system is effectively isolated (a)What is the mass of the second cart? (b)What is the total momentum of the system? (c)What...
Two manned satellites approaching one another, at a relative speed of 0.150 m/s, intending to dock. The first has a mass of 3.50 x 10^3 kg, and the second a mass of 7.50 x 10^3 kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was orginally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) (b) What...
An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.30×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...
An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.50×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...
An alpha particle with kinetic energy 12.0 MeVmakes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.20×10−13 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of...
A 1-kg ball in the air has an initial velocity vo = [ -20 ] i + [ -20 ] j m/s. It falls for a total time of 1 s. Assume that positive x-values are to the right and positive y-values are upward. What is the initial momentum pi of the ball? -20 i + -20 j kg*m/s What is the impulse or change in momentum ∆p of the ball? 0 i + -10 j kg*m/s What is the final momentum pf of the ball?...
I need help with all of the questions! Thank you 1). Momentum (P) of an object is a vector quantity a) True b) False c) Can's say 5 m/s' is 2). Momentum of an object of mass 'm = 10 Kg' moving with a velocity v a) 50 Ns b) 50 Nm c) 50 N/s 3). How the force (F) and momentum (P) are related, do not forget to show the vector sign 4). For an isolated system, momentum is...
The acceleration definition a (vf-vo/At Final velocity vf v0+a t Multiply by mass m*vf mvo+ m'aAt so that m'vf m'v+F At Momentum mass velocity Impulse F At Velocity and KE values in a collision would depend on the observer reference frame KE 0.5*m v v pp/2m when momentum p -m'v A lab frame observer reported that a 3 kg impactor-A moving at 15 m/s collided with a stationary 10 kg target-B on a smooth table. 1a- Find the velocity magnitude...
HELLO! Please answer all the questions! don't leave any of them out! Thanks! Answer all the questions asked please! om 8. A ball of silly putty hits and sticks to a bowling ball that was initially at rest. After the collision, the total kinetic energy of the bowling ball and silly! putty is O (A) less than the kinetic energy of the silly putty before the collision O (B) more than the kinetic energy of the silly putty before the...