Question

Question 1 8 pts Use the table of data below to answer the following question. Which of these correctly has the linear velocity of the ankle in both the horizontal (X) and vertical (Y) directions as determined by using the First Central Difference formula for times 0.083 and 0.091 sec. (8 pts) Time (s) AnkleX(mm)AnkleY(mm) 0.075 712.6 163.3 0.083 727.4 175.9 0.091 738.9 186.7 0.099 750.0 199.9 Time (s) 0.083 0.091 Vx (mm/s) 1850 1438 Vy (mm/s) 1575 1350 Time (s) 0.083 0.091 Vx (mm/s) 1644 1413 Vy (mm/s) 1463 1500 Time (s) 0.083 0.091 Vx (mm/s) 8764 8120 Vy (mm/s) 2119 2052

Answer 1

solution I consider the above given that by using the first central difference formula.. f(t+h)-f(t-h) : Taken hom the rdues intable Ankle x'coes/ - Anklex(0.0911 - Anklexlo.075 2 10.08 3-0.075) 738.9-712.6 = 1643.75 210.008) ñ 16 tedy Ankle x'(0.091) - Ankle x 10.099) - Anklexl0.083) 2 (0.099 - 0.091) 750-727.4 = 1412.5 2 (0.008) a 1413 Ankle y (0.083) = Ankle y(0.091) - Ankle 9 (0.075) = 210.083 -0.075) 186.7-163.3 CE 1462.5 N 1463 210.008)

Ankle y' (0.091) - Ankley(0.099) - Ankley (0.083) 210.099-0.0911 199.9-175.9 2 (0.008) -1500 Time (s) Vx (MM/s) Vy Inm/s) 16444 0.083 0.09) 1463 1500 1413 And option is correct