Question 1 As shown in Figure 1, the belt passing over the pulley is subjected to...
The belt passing over the pulley is subjected to forces F1 and F2, each having a magnitude of 40 N. F1 acts in the −k direction. Set θ=0∘ so that F2 acts in the −j direction. (Figure 1) Determine the equivalent force. Express the result in Cartesian vector form. r80 mm 300 mm
The screw eye is subjected to the two forces shown in (Figure 1) Part E Find the coordinate direction angle α of the resultant force Part F Find the coordinate direction angle β of the resultant force
The bracket is subjected to the two forces shown. Express each force in Cartesian vector form and then determine the resultant force FR. Given that F2 = 480 N (Figure 1)Part A Find the magnitude of the resultant forcePart B Find coordinate direction angle α of the resultant force
A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a motor through a belt with the belt tensions shown. The power is transmitted through the shaft and delivered to the belt on pulley B. Assume the belt tension on the loose side at B is 15 percent of the tension on the tight side. Yield of the Shaft ?? = 560 ??? a) Determine the tensions in the belt on pulley B, assuming...
Replace the forces acting on the L-shaped bracket with the following force-couple systems. Neglect the thickness of the bar in your calculations. (Express the resultant forces in vector form in newtons.) 290 NA 190 mm 480N 190 mm cDE I 190 mm 190 mm 190 N (a) an equivalent force-couple system that acts at point A Indicate the magnitude in N.m and direction of the couple moment, magnitude Nm direction -Select- (b) an equivalent force-couple system that acts at point...
[1] The screw is subjected to the four forces shown. Express each force in Cartesian vector form and then determine the resultant force. Find the magnitude and direction angles of the resultant force. F1-400 N F-150N 600 120 45° Fs-250 N 45 60- F:-600 N
Problem-1.2 The hook shown in the Figure below is subjected to three forces shown in F1, F2 and F3. a) Find the resultant of the force F1 and F2 and call it FA. Use parallelogram law to find the magnitude and direction of the force FA b) Find the magnitude and direction of the force F3, if the resultant FR of the all three forces is 750 N and it is directed along the x-axis.
Problem 1 (50 points) A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a motor through a belt with tensions shown. The power is transmitted through the shaft and delivered to the belt on pulley B. Assume the belt tension on the loose side at B is 15 percent of the tension on the tight side. 230 mm F: 30-mm dia. 280 mm 300 mm 250-mm dia. 400-mm dia 1000 N 150 N...
[1] The cables attached to the eyebolt are subjected to the three forces shown. Express each force in Cartesian vector form and determine the magnitude and coordinate direction angles of the resultant force.
3. The bracket is subjected to the two forces shown. Express each force in Cartesian vector form and then determine the resultant force FR. Find the magnitude and coordinate direction angles of the resultant force. F, = 400 N 60° 45° 120 25° 35° F, = 250 N