Question

How to calculate unreacted concentration of A at 2hr when rate = k[A]1[B]0 (first order A,...

How to calculate unreacted concentration of A at 2hr when rate = k[A]1[B]0 (first order A, zero order B) ? A + B --> C, 1hr: A 75% reacted

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A + B -------> C,

With in one hour 75 % of A is reacted that means 25 % A is remaining

in another one hour 75 %

taht means 75% of 25 = 75/100 (25) = 18.75 will finish after 2 h

after 2 hours 6.25 % will remain

Add a comment
Know the answer?
Add Answer to:
How to calculate unreacted concentration of A at 2hr when rate = k[A]1[B]0 (first order A,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 3 1 pts The rate constant, k, of the first order reaction A B +C...

    Question 3 1 pts The rate constant, k, of the first order reaction A B +C is k = 8.62 x 10-35-1. If the initial concentration of A is 2.74 M, how long will it take for the concentration of A to fall below 0.32 M? Give your answer to one decimal place in MINUTES (do not input the units). For example, if your answer is 8.956 minutes, enter 9.0 Question 4 1 pts The rate constant, k, of the...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k k and not on the reactant concentration. It is expressed as t1/2=0.693k t 1 / 2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0. A certain first-order reaction (A→products A → p r o d u c t s ) has a rate constant of 9.30×10−3...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...

  • A first-order reaction A⟶BA⟶B has the rate constant k=k= 2.8×10−3 s−1s−1 . If the initial concentration...

    A first-order reaction A⟶BA⟶B has the rate constant k=k= 2.8×10−3 s−1s−1 . If the initial concentration of AA is 1.5×10−2 MM, what is the rate of the reaction at t=t= 690 ss ? Express your answer to two significant figures and include the appropriate units.

  • Learning Goal: To understand how to use integrated rate laws to solve for concentration. A car...

    Learning Goal: To understand how to use integrated rate laws to solve for concentration. A car starts at mile marker 145 on a highway and drives at 55 mi/hr in the direction of decreasing marker numbers. What mile marker will the car reach after 2 hours? This problem can easily be solved by calculating how far the car travels and subtracting that distance from the starting marker of 145. 55 mi/hr×2 hr=110 miles traveled milemarker 145−110 miles=milemarker 35 If we...

  • 1) A stoichiometric reaction is . Initial concentrations of A and B are each 1 M....

    1) A stoichiometric reaction is . Initial concentrations of A and B are each 1 M. At the end of 1 hour, A is 90% reacted. Through a set of rigorous kinetics experiments, you also determined that the reaction is first order in A and zero order in B and C. a) Write the rate law for this reaction. (e.g. = ...) b) What is the rate constant? Use correct units. c) How much of A will be left unreacted...

  • 1. A reaction is second order in[A] and second-order in [B]: Rate,=K[A]^2[B]^2. what are the units...

    1. A reaction is second order in[A] and second-order in [B]: Rate,=K[A]^2[B]^2. what are the units of k for this reaction? If the concentration of air decreases by a factor of 2 and the concentration of b increases by a factor of 5 what happens to the rate? 2. for the forward reaction 2NO+Cl2=>2NOCl. determine the rate(m/s)for experiment #4 given [NO]°(M)=0.40M and [Cl2]°z(M)=0?20M. Rate? 3.The following data were collected over time for the forward reaction 2NO2=>2NO+O2 ( 1/[NO2]=100 at 0...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as 0.693 - 1/2K For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as 1/2 k(Alo Part A A certain first-order reaction (A>products) has a rate constant of 9.60x10 s-1 at45 C. How many minutes does it take for the concentration of the...

  • Derive the equation 1/[B] = 1/[B]_0 + kt from the instantaneous rate of reaction in terms...

    Derive the equation 1/[B] = 1/[B]_0 + kt from the instantaneous rate of reaction in terms of B and rate = k[B]^2. What are the units of k if concentration is expressed in molarity and time in seconds a. For a first order reaction? b. For a second order reaction? c. For a zero order reaction? d. For a reaction that follows the rate equation, rate = k[A] [B]^1/2? The rate law for a reaction only involves the reactant A...

  • The reaction C H → 2C H is first order with rate constant k = 1.89...

    The reaction C H → 2C H is first order with rate constant k = 1.89 x 10-1 s-1. 48 24 a. Suppose that [C4H8]0 = 0.265 M. How long (in seconds) will it take for the concentration of C4H8 to decrease to 45.0% of its initial value

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT