Question

What is the best procedure to prepare 0.500 L of a 0.200 M solution of Li3PO4? The molar mass of Li3PO4 is 115.8 g.mol-1 Data sheet and Periodic Table Weigh 11.6 g of solute and add 0.500 L of water. Weigh 23.2 g of solute and add 0.500 L of water. Weigh 11.6 g of solute and add sufficient water to obtain a final volume of 0.500 L. Weigh 23.2 g of solute and add sufficient water to obtain a final volume of 0.500 L.

Answer 1

= 15.8 gimol to He have of Liz Pou. He will use some formulaes, Molarity مج * Li₂ POL water & dilute it upto 0.5ool so option and Correet lie. Heigh 11.6 g. Solute to add sufficient Waters for final volume. Answer :- Option 3rd is correct of explained belowe - Given values o molar mass of liz Pou prepare 0.500L of a 0.200 m solution number of moles of solute Yolume of solution in lines moles of solute Amount of solute molar mass of solute solute = i molarity we want = 0.20on. Volume of solution we want = 0.500L By putting values in formula, number of moles of solute 0200 0.500 number of moles of solure = 0:1 mol Amount of solute 115.8 .. Amount of solute 11:58 Ñ More that final volume of solution we want is 0.500L so we will dissolve this 11.6g. Of Lig Pous in sufficient is 0.1 11.6 g * of 0.500 l CS$canned with CamScanner