Question

4. The 2-kg spool sfits loosely on the inclined rood for which the coefficant of Static friction lo 02 Il espaol is located 0:25 m m A, defecane the maximum constant speed the spark.com have so that it does not slip up the role Home Work 1.2 The 10 16 block has a speed of 4 pels when the force of Fis62 16 is appliedo Determine the velocity of the block when t=as. The coefficient of kinetic friction at the surface is x = 0.2 The coefficio of Kinetic friction beloween the sorg date and the ground is lle - 0.30 determine the sincete care tpavels and its Velocity what 35. The cate Stads Exam Cest, sed Pe LOON The 20 kg cafe is soyecel le a force having a constat Liceekin la d e os seus 16h, the cale is moving to thy sight with a pood of a m/s.. Debesis ils pouw the cele of kete fodlien be the code and the ground is 25 The de bock Band 15-y Gelinder ore Comeefae to a light, chood that passes through a hole in the center of the smooth table. If the block is given a speed of soms Reten te fokus of filee the acalar path along which it fravels. 6. The acade, ich has c f t , is secretotle schon of the foo force. T a iginally frest, Lcheinum te Aslanda i slide in the fall speed of Ense The cont y Binale fcchio be the sale e le sifa SED SOON 30

Answer 1

1.

FBD N fm F ma

The values provided in the question are,

v_o = initial velocity = 4 ft/s,

t = time taken by block = 2s

m = mass of block = 10 lb

F = force on block = 862 lbF

Coefficient of kinetic friction,

Mk = 0.2

we know, g = acceleration due to gravity = 32 ft/s²

Let, a = acceleration of the block

Required, v = final velocity after 2s

FORMULA USED :

Formula-1 :

Fy= may

so, from FBD drawn above,

V = mg

Formula-2 :

Force of kinetic friction,

buyr = N = {

(On putting the value of N from Formula-1)

Formula-3 :

ΣF, = mar

so, from FBD drawn above,

  

F-f=ma

On putting the value of f from Formula-2,

F - Mimg = ma

F - μmg

Formula-4 :

V = Ve + at

SOLUTION :

using Formula-4 and substituting a from above, we get

F-ukmg y = vo + ( — ш

On putting the values from above data, we get

(ANSWER)

v=v0+( Mmg +-1 (862 – (0.2) * 10 * 32) 2* (2) = 163.6 ft/s 7 10