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When a 0.452 kg mass is hung from a certain spring it stretches 0.154 m to its equilibrium position at a point P. If this mas
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Answer #1

given

mass m = 0.452 kg

spring constant k = 0.452*9.8/0.154 = 28.76 N/m

acceleration a = kx/m

a = 28.76*0.143/0.452 = 9.1 m/s^2

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