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An insulated Thermos contains 114 cm3 of hot coffee at 69

An insulated Thermos contains 114 cm3 of hot coffee at 69

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Answer #1

Change all the temp. to Kelvin first. Ice is 0C in solid form so there is a latent heat too.
4186(114/1000)(342-T)=333x1000x12/1000 + 4186(12/1000)(T-273)

Solve for T?
Then (T-273) is in Celsius.
Difference = 69 - (T-273)

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Answer #2

Energy gained by ice = m_ice * (h_sf + cpw*T)
Energy lost by coffee = ?_w*V_coffee*cpw*(89 - T)

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