An insulated Thermos contains 114 cm3 of hot coffee at 69
Change all
the temp. to Kelvin first. Ice is 0C in solid form so there is a
latent heat too.
4186(114/1000)(342-T)=333x1000x12/1000
+ 4186(12/1000)(T-273)
Solve for
T?
Then
(T-273) is in Celsius.
Difference
= 69 - (T-273)
Energy gained by
ice
= m_ice * (h_sf + cpw*T)
Energy lost by
coffee
= ?_w*V_coffee*cpw*(89 - T)
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