What is the pH of a buffer solution that is 0.400 M in HF and 0.790 M in NaF? Ka of HF = 7.2 ✕ 10-4.
PH = PKa + log[NaF]/[HF]
Ka = 7.2*10-4
PKa = -logKa
= -log7.2*10-4
= 3.1426
PH = 3.1426 + log0.79/0.4
= 3.1426 + 0.2955 = 3.4381 >>>>> answer
What is the pH of a buffer solution that is 0.400 M in HF and 0.790...
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