To solve this problem,we'll first compute the mean and stabdard deviation of the given data through average and and STDEV function in Ms Excel respectively.
Mean of the data = 3883.3
(Process mean= sum of all the demands of the week/no of week=23300/6= 3883.3) we can also find that
Average = 3883.3
Standard deviation =274.9
[(Variance=sum of (average-demand of week)²/6
Std deviation of the demand= sqrt(variance)]
Given that the required sigma levels =3
Now
UCL =Mean+3SD= 3883.3+3(274.9)=4708
LCL=Mean-3SD= 3883.3-3(274.9)=3058.6
Please show in Excel 7.4 Using the following weekly demand data for a new soft drink,...