Homework Answers
Reduction- gain of Electron is called reduction.
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Consider the following unbalanced reaction: 1035(aq) + (aq) + H+(aq) → 12(s) + H2O(1) The correctly...
Please show all steps taken (prefer typed solution) Half-Reaction E ° (V) Ag+ (aq) + e−...
Please show all steps taken (prefer typed solution)
Half-Reaction
E
°
(V)
Ag+ (aq) + e− → Ag (s)
0.7996
Al3+ (aq) + 3e− → Al (s)
−1.676
Au+ (aq) + e− → Au (s)
1.692
Au3+ (aq) + 3e− → Au (s)
1.498
Ba2+ (aq) + 2e− → Ba (s)
−2.912
Br2 (l) + 2e− → 2Br− (aq)
1.066
Ca2+ (aq) + 2e− → Ca (s)
−2.868
Cl2 (g) + 2e− → 2Cl− (aq)
1.35827
Co2+ (aq) + 2e−...
Which of the following is easiest to oxidize? a. H2(g) b. Zn(s) c. Ag(s) d. H2O(l)...
Which of the following is easiest to oxidize? a. H2(g) b. Zn(s) c. Ag(s) d. H2O(l) e. Cu(s) The half?reaction occurring at the cathode in the balanced reaction shown below is ________. 3MnO4 ? (aq) + 24H+ (aq) + 5Fe (s) ? 3Mn2+ (aq) + 5Fe3+ (aq) + 12H2O (l) a. MnO4 ? (aq) + 8H+ (aq) + 5e? ? Mn2+ (aq) + 4H2O (l) b. 2MnO4 ? (aq) + 12H+ (aq) + 6e? ? 2Mn2+ (aq) + 3H2O (l) c. Fe (s) ? Fe3+ (aq) + 3e? d. Fe (s) ? Fe2+ (aq) + 2e? e. Fe2+ (aq) ? Fe3+ (aq) + e can you explain in detail? I have no clue what is going...
The following is an unbalanced redox reaction: Unbalanced Reaction: Al(s) + Co2+(aq) --> Al3+(aq) + Co(s)...
The following is an unbalanced redox reaction: Unbalanced Reaction: Al(s) + Co2+(aq) --> Al3+(aq) + Co(s) (a) Balance the above reaction using the half-reaction method. Show work. (b) The standard reduction potential for Al3+ to Al is ?red ° = −1.662 ? and the standard reduction potential for Co2+ to Co is ?red° = −0.277 V. Given this information, maximum amount of work, in kJ/mol rxn, for the balanced redox reaction from part (a) above. (T = 25.0 °C) Show...
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG...
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG for the following redox reaction. Round your answer to 3 significant digits Mn (aq)+2H,O()+2Fe (aq)MnO, ()+4H (aq)+2Fe (aq) dhData Cu (aq) + e Cu (5) F2 (0)+2e2F (aq) Fe (aq) +2e Fe (s) Fe (aq) + eFe2 (aq) Fe (aq) + 3e Fe (s) 2.866 X ? -0.447 0.771 -e.037 2H (aq)+2e H (0) e.000 2H)O (I)+2e H2 (a) +20H(aq) -0.8277 1.776 H2O2 (aq)...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) +...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) + 2e - → H2(g) 0.000V Cr3+(aq) + 3e —— Cr(s) -0.740V The strongest oxidizing agent is: enter formula The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will 12(s) reduce Cr3+(aq) to Cr(s)? — Which species can be reduced by H2(g)? If none, leave box blank. Use the References to access important values if needed for this question....
olo Data Х -0.8277 1.776 0.5355 1.195 -2.372 -1.185 1.224 1.507 0.595 0.983 -1.16 2H20 (1)...
olo Data Х -0.8277 1.776 0.5355 1.195 -2.372 -1.185 1.224 1.507 0.595 0.983 -1.16 2H20 (1) + 2e - H2(g) + 20H(aq) H2O2 (aq) + 2H+ (aq) + 2e - 2H20 (1) 12 (s) + 2e - 21- (aq) 2103 (aq) + 12H+ (aq) + 10 → 12 (5) + 6H20 (1) Mg2+ (aq) + 2e - Mg(s) Mn2+ (aq) + 2e – Mn (s) MnO2 (s) + 4H+ (aq) + 2e – Mn2+ (aq) + 2H20 (1) Mn04- (aq)...
A certain half-reaction has a standard reduction potential +0.14 V. An engineer proposes using this half-reactio...
A certain half-reaction has a standard reduction potential +0.14 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 0.80 V of electrical power. The cell will operate under standard conditions Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. Is there a minimum standard reduction potential that the hall reaction used at the cathode of this cell can have? ves, there...
A certain half-reaction has a standard reduction potential E = -0.45 V. An engineer proposes using...
A certain half-reaction has a standard reduction potential E = -0.45 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that must provide at least 1.00 V of electrical power. The cell will operate under standard conditions Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. 0-0 . " Is there a minimum standard reduction potential that the half-reaction used at the anode of this cell...
Piece #1 (1/2 pt) Consider the following reaction (unbalanced): MnO2 (s) + H3AsO3(aq) -Mn²+ (aq) +...
Piece #1 (1/2 pt) Consider the following reaction (unbalanced): MnO2 (s) + H3AsO3(aq) -Mn²+ (aq) + H2AsO(aq) Split the reaction into two half-reactions. Oxidation half reaction: H:AsO3(aq) → H3 AsO, (aq) Reduction half reaction: MnO2 (s) Mn (aq) Piece #2 (1/2 pt) Consider the following half-reaction: MnOz(s) - Mn2+ (aq) Balance everything but oxygen and hydrogen atoms. MnO2 (s) + 2e Mn (aq) Piece W3 (1/2 pu) Take your answer to Piece #2 and balance the oxygen by adding a...
Balance the following half-reaction by adding the appreciate number of electrons. Fe^2+ (aq) --> Fe^3+ (aq)...
Balance the following half-reaction by adding the appreciate number of electrons. Fe^2+ (aq) --> Fe^3+ (aq) AgI(s) --> Ag(s)+I^-(aq) VO2^+(aq)+2H^+(aq) --> VO^2+(aq)+H2O(l) I2(s)+6H2O(l) --> 2IO3^-(aq)+12H^+(aq)
Please show all steps taken (prefer typed solution)
Half-Reaction
E
°
(V)
Ag+ (aq) + e− → Ag (s)
0.7996
Al3+ (aq) + 3e− → Al (s)
−1.676
Au+ (aq) + e− → Au (s)
1.692
Au3+ (aq) + 3e− → Au (s)
1.498
Ba2+ (aq) + 2e− → Ba (s)
−2.912
Br2 (l) + 2e− → 2Br− (aq)
1.066
Ca2+ (aq) + 2e− → Ca (s)
−2.868
Cl2 (g) + 2e− → 2Cl− (aq)
1.35827
Co2+ (aq) + 2e−...
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG for the following redox reaction. Round your answer to 3 significant digits Mn (aq)+2H,O()+2Fe (aq)MnO, ()+4H (aq)+2Fe (aq) dhData Cu (aq) + e Cu (5) F2 (0)+2e2F (aq) Fe (aq) +2e Fe (s) Fe (aq) + eFe2 (aq) Fe (aq) + 3e Fe (s) 2.866 X ? -0.447 0.771 -e.037 2H (aq)+2e H (0) e.000 2H)O (I)+2e H2 (a) +20H(aq) -0.8277 1.776 H2O2 (aq)...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) + 2e - → H2(g) 0.000V Cr3+(aq) + 3e —— Cr(s) -0.740V The strongest oxidizing agent is: enter formula The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will 12(s) reduce Cr3+(aq) to Cr(s)? — Which species can be reduced by H2(g)? If none, leave box blank. Use the References to access important values if needed for this question....
olo Data Х -0.8277 1.776 0.5355 1.195 -2.372 -1.185 1.224 1.507 0.595 0.983 -1.16 2H20 (1) + 2e - H2(g) + 20H(aq) H2O2 (aq) + 2H+ (aq) + 2e - 2H20 (1) 12 (s) + 2e - 21- (aq) 2103 (aq) + 12H+ (aq) + 10 → 12 (5) + 6H20 (1) Mg2+ (aq) + 2e - Mg(s) Mn2+ (aq) + 2e – Mn (s) MnO2 (s) + 4H+ (aq) + 2e – Mn2+ (aq) + 2H20 (1) Mn04- (aq)...
A certain half-reaction has a standard reduction potential +0.14 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 0.80 V of electrical power. The cell will operate under standard conditions Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. Is there a minimum standard reduction potential that the hall reaction used at the cathode of this cell can have? ves, there...
A certain half-reaction has a standard reduction potential E = -0.45 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that must provide at least 1.00 V of electrical power. The cell will operate under standard conditions Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. 0-0 . " Is there a minimum standard reduction potential that the half-reaction used at the anode of this cell...
Piece #1 (1/2 pt) Consider the following reaction (unbalanced): MnO2 (s) + H3AsO3(aq) -Mn²+ (aq) + H2AsO(aq) Split the reaction into two half-reactions. Oxidation half reaction: H:AsO3(aq) → H3 AsO, (aq) Reduction half reaction: MnO2 (s) Mn (aq) Piece #2 (1/2 pt) Consider the following half-reaction: MnOz(s) - Mn2+ (aq) Balance everything but oxygen and hydrogen atoms. MnO2 (s) + 2e Mn (aq) Piece W3 (1/2 pu) Take your answer to Piece #2 and balance the oxygen by adding a...
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