Question

How many 6 digit numbers can be formed if the number formed must be divisible either 5 or 2, AND this number can't begin with a 0, e.x. 0538... is not allowed? What are possible arrangements?

¿Cuántos números de 6 dígitos se pueden formar si el número formado debe ser divisible ya sea 5 o 2, Y este número no puede comenzar con un 0, e.x. 0538 ... no está permitido? ¿Cuáles son los posibles arreglos?

Answer 1

8 > for & no. no. of 6 digit number which is dirisble by 2 ends with either 0, 2, 4, 6, therefore unit place can be filled by 5 ways. and the tenth place can be fitted by 10 ways, houndredth thousand ten thousand and the last one can be filled exceps 10 ways. 10 ways 10 ways. a ways, So total no • of to numbers which êş dinisible نے 2 ط 450000 ways 9 X 10 X10X10X10X5 divisibility with s tunit place must be either soro So can be filled by 2 ways, numbers (six digit) which is livesible és 9 X 10 X 10 X 10x10x2 no by s 180000 ways. divisible by both 2 and s unuit place must be one way 6 digit numbers 9X10X10X10 X10XT = 90000 total no. of 6 digft number which is divisible by tot 450000 + 180000 - 90000 a noo of 5 or 2 540000 0