Question

İ Question Help * The table below contains the amou that a sample of nine customers spent for lunch i$ at a fast-food restamrant Complete parts a and b below 4.62 5.22 566 647 7.47 763 8.12 832 965 a. Constrctぁ95% oonfonce nterval estisile Or te population mean amont spet fork nch at a fast food restaurant assured a nonna aantain The % confieren niervol estrate is from S576 la S828 (Round to two decimal places as needed.) b. Interpret the imervai constructed in (e) Choose the correct answer beie A. B. 0 С. Ο D. 95% of the sanpe data tai between the inns r this condene interva. we have se% contoence hat the mean amount in dolars spent for lunch at the fast-food resaurre inr the The mean armourts in olars spent fur urea, the tasHood restaurant o, 95% of al samples of lhe same sze ve contaned n te nterval we have 95% confidence that the populainn mein amount in dlars spent for luch at รา e tast-food restaurant is contared rte ntersa' mole is contained in he it." elg

Answer 1

Solution:- Given that sample 4.62,5.22,5.66,6.47,7.47,7.63,8.12,8.32,9.66

X = 7.0189, s = 1.6430 , n = 9 , df = 8

t = 2.306

95% confidence interval for the population mean = X +/- t*s/sqrt(n)
= 7.0189 +/- 2.306*1.6430/sqrt(9)
= 5.76 , 8.28

=> option D.

Note : first of all values are not clear. my process was correct and explanation also