Question

The cheetah is the fastest land mammal and is highly specialized to run down prey. The cheetah often exceeds speeds of 60 miles per hour (mph) and is capable of speeds above 72 ple Tha inalahiaantaina amalaaha de af 2E hestebe X i Top Speeds of Cheetahs (mph) 52.1 52.5 54.5 54.8 55.4 55.7 56.1 56.5 57.1 57.5 57.6 57.8 57.8 58.2 58.3 58.7 59.1 59.2 59.6 59.7 59.9 60.1 60.3 60.6 60.8 60.9 61.4 61.7 62.3 63.1 63.4 64.7 65.4 67.1 75.2 Print Done c. Use the data to obtain the exact percentages of observations that lie within one, two, and three standard deviations to either side of the mean. Practice % of observations lie within one standard deviation to either side of the % of observations lie within two standard deviations to either side of the mean, Using the data, Q: The c speec mean % of observations lie within three standard deviations to either side of the mean. samp 59.52 and (Type integers or decimals. Round to one decimal place as needed.) A: See an ? Enter your answer in the edit fields and then click Check Answer. 1 part remaining Clear All Check Answer Question Q: A sampl
pls explain about C.

Answer 1

Solution:-

Data Mean 59.57429 Standard Error 0.734656 Median 59.2 Mode 57.8 Standard Deviation 4.346286 Sample Variance 18.8902 Kurtosis 3.875208 Skewness 1.312342 Range 23.1 Minimum 52.1 Maximum 75.2 Sum 2085.1 Count 35

Interval for containing observations within one standard deviation is 59.575 + 4.346 or (55.23, 63.92)

Interval for containing observations within two standard deviation is 59.575 + 2*4.346 or (50.88, 68.27)

Interval for containing observations within three standard deviation is 59.575 + 3*4.346 or (46.54, 72.61)

a)

Number of observations within one standard deviations = 27

Total number of observations = 35

Percentage of observation within one standard deviation = (27/35)*100

Percentage of observation within one standard deviation is 77.14%

b)

Number of observations within two standard deviations = 34

Total number of observations = 35

Percentage of observation within two standard deviation = (34/35)*100

Percentage of observation within two standard deviation = 97.14%

c)

Number of observations within three standard deviations 34

Total number of observations = 35

Percentage of observation within three standard deviation = (34/35)*100

Percentage of observation within three standard deviation is 97.14%