Question

A proton moves to the left with a speed of 1.25 · 106 m/s into a region of constant magnetic field as shown in the figure below. The magnitude of the magnetic field is 1.91 · 10-2 T and the direction of the field is into the page.

When the proton initially enters the magnetic field, the magnitude of the force on the proton (in N) is

A: 2.160×10-15 B: 2.872×10-15 C: 3.820×10-15 D: 5.081×10-15 E: 6.757×10-15 F: 8.987×10-15 G: 1.195×10-14 H: 1.590×10-14

When the proton initially enters the magnetic field, the direction of the force on the proton is

A: toward the top of the page B: toward the bottom of the page C: into the page . D: out of the page . E: to the right of the page F: to the left of the page

Answer 1

Force (F) = qVB = 1.6 times 10^- 19 times 1.25 times 10^6 times 1.91 times 10^- 2 = 3.82 times 10^- 15 N option (C) Direction: to the right of the page option (E)