4. 1-/1 Points) DETAILS SCALCET8 3.1.070. Find a parabola with equation y = ax + bx...
6. [-12 Points] DETAILS SCALCET8 14.5.012. Use the Chain Rule to find Oz/os and Oz/t. z = tan(u/v), u = 6 + 9t, v = 9s - 6t дz as oz at Need Help? Read It Talk to a Tutor 7. [-13 Points] DETAILS SCALCET8 14.5.021. Use the Chain Rule to find the indicated partial derivatives. z = x4 + x2y, x = 5 + 2t - u, θz oz oz when s = 4, t = 3, u =...
Find a parabola with equation y = ax2 + bx + c that has slope 13 at x = 1, slope -19 at x = -1, and passes through the point (1, 13). y =
The equation for a parabola has the form y=ax^2+bx+c, where a, b, and c are constants and a≠0. Find an equation for the parabola that passes through the points (−1,0), (−2,−1), and (−6,15). Answer: y =
Find an equation of the form y=ax'+bx+c that defines the parabola through the three noncollinear points given. (0,6), (5, 46),(-2, 4) The equation of the parabola is y-
Please explain and show work. Thank you The equation of a parabola is y ax + bx c, where a, b, and c are constants. The x and y-coordinates fa projectile launched from the origin as a function of time are given by x vt and y - vt where v and vun are the components the initial velocity. ax2 (a) Eliminate t from these two equations and show that the path of a projectile is a parabola and has...
31. [-/1 Points) DETAILS SCALCET8 3.3.027. If f(x) = 5 sec(x) - 3x, find f'(x). f'(x) = Need Help? Read It Watch It Talk to a Tutor 32. [-/2 points) DETAILS SCALCET8 3.3.028. If f(x) = 20% cos(x), find f '(x) and F"(x). F'(x) = F"(x) = Need Help? Read it Talk to a Tutor 33. [-/2 Points) DETAILS SCALCET8 3.3.029 If H() = sin(e), find Hle) and H) HO) = HD) -
Pleaseee help with BOTH problems, sketching and how to find the area please? [-/1 Points) DETAILS SCALCET8 6.1.003. Find the area of the shaded region. x = y2 - 4 y = 1 x -2 2 4 y = -1 Need Help? Read It Watch It Talk to a Tutor Submit Answer [-/1 Points) DETAILS SCALCET8 6.1.004. Find the area of the shaded region. x = y2 - 4 y (3) -6 -5 -4 -3 1 Need Help? Read It...
Find the equation of the tangent line to the parabola at the given point. y = -3x2, (-4,-48) y + 48 = -3x²(x + 4) X Read It Talk to a Tutor Need Help?
4. [-16 Points] DETAILS SCALCCC4 3.4.090. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Find the tangent equation to the given curve that passes through the point (10, 10). Note that due to the t2 in the x equation and the t3 in the y equation, the equation in the parameter t has more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point. x = 6t2 + 4...
12. [-/1 Points] DETAILS SCALCET8 A.E.044. Find the limit. ..om :11 +1] Need Help? Read It Talk to a Tutor Submit Answer