ZuoTi.Pro
Question

What is the magnitude and direction of the magnetic field in the region?

A particle with a charge q=8.5x10-6 C and a mass of 3.1x10-12 kilograms has a velocity of Vo=2.5x103 meters per second as it goes into a region of uniform magnetic field. The particle travels in a semicircular path (shown) with a radius of 5 centimeters. What is the magnitude and direction of the magnetic field in the region? 3196D742-FF20-4004-856D-E02485F7C70F.jpeg

physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)

All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
What is the magnitude and direction of the magnetic field in the region?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Similar Homework Help Questions

  • Figure 20.12 region of magnetic field 1 Path of the particle 1) In Figure 20.12, a...

    Figure 20.12 region of magnetic field 1 Path of the particle 1) In Figure 20.12, a small particle of charge q =-1.9 x 10-6 C and mass m 3.1 x 10-12 kg has velocity vo 8.1 x 103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R 5.0 cm. Calculate the (a) magnitude and (b) direction of the magnetic field in the region.

  • 5. A small particle of velocity vo-8.1 × 103 m/s asit enters a region of uniform...

    5. A small particle of velocity vo-8.1 × 103 m/s asit enters a region of uniform magretic field. The particle is observed to travel in the semicircular path with radius R 5.0 cm. Cakculate the (a) magnitude and (b) direction of the magnetic fleld in the region charge q-1,9 x 10-6 C and mass m "3.1x10-12kg has

  • Item 15 Part A As shown in the figure, a small particle of charge q =-8.7...

    Item 15 Part A As shown in the figure, a small particle of charge q =-8.7 ×10-6 C and mass m = 3 1x 10-12 kg has velocity vo = 10.0 × 103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R 5.0 cm. Calculate the magnitude and direction of the magnetic field in the region Region of magnetic field IPath of the ptcle Im...

  • magnetic field directed

    In the figure, a small particle of charge = -2.0 × C and mass kg has velocity m/s as it enters a region of uniform magnetic field. Theparticle is observedto travel in the semicircular path shown, withradius = 5.0 cm.maginitude of the magnetic field is0.24 Tmagnetic field directed:to the right.to the leftinto the screenout of the screen

  • A proton enters a region of constant magnetic field, perpendicular to the fie and after being...

    A proton enters a region of constant magnetic field, perpendicular to the fie and after being accelerated from rest by an electric field through an electric potential difference of - 350 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 21 cm. mt As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will...

  • 3. (a) Show that when a particle with mass m and charge q enters a magnetic...

    3. (a) Show that when a particle with mass m and charge q enters a magnetic field having its velocity v perpendicular to the direction of the magnetic field B, it will perform a mv circular path of radius R- qB (b) Using the previous result find an expression for the period T of the circular motion. (c) A charged particle moves into a region of uniform magnetic field, goes through half a circle and then exits that region, as...

  • I know it can be done using Right Hand Rule, but don't know how to solve it practically. Please help explain how to apply right-hand rule actually. Thanks! A small charged particle of charge q7....

    I know it can be done using Right Hand Rule, but don't know how to solve it practically. Please help explain how to apply right-hand rule actually. Thanks! A small charged particle of charge q7.0 x 10-6C and mass m - 3.1 x 10-12kg is accelerated through a potential difference of 19.6V before it enters a region of uniform magnetic field as shown by the rectangle in the following figure. The particle is observed to travel in the semicircular path...

  • An alpha particle travels at a velocity of magnitude 460 m/s through a uniform magnetic field...

    An alpha particle travels at a velocity of magnitude 460 m/s through a uniform magnetic field of magnitude 0.056 T. (An alpha particle has a charge of charge of +3.2 × 10-19 C and a mass 6.6 × 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 61°. What is the magnitude of (a) the force acting on the particle due to the field, and (b) the acceleration of the particle due to this...

  • An alpha particle travels at a velocity of magnitude 580 m/s through a uniform magnetic field...

    An alpha particle travels at a velocity of magnitude 580 m/s through a uniform magnetic field of magnitude 0.046 T. (An alpha particle has a charge of charge of +3.2 × 10-19 C and a mass 6.6 × 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 56°. What is the magnitude of (a) the force acting on the particle due to the field, and (b) the acceleration of the particle due to this...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT