Question

FULL SCREEN PRINTER VERSION ·BACK NEXT Chapter 11, Problem 030 Two identical containers are open at the top and are connected at the bottom via a tube of negligible volume and a valve that is closed. Both containers are filled initially to the same height of 1.00 m, one with water, the other with mercury, as the drawing indicates. The valve is then opened. Water and mercury are immiscible. Determine the fluid level in the left container when equilibrium is reestablished. Valve Number Units the tolerance is +/-2% question Attempts: Unlimited SAVE FOR LATER SUBHIT ANSWER Version 4.24.2.4 &Sons Inc All Rights Reserved. A Division of John Wley &Sons.Inc

Answer 1

mass of 1 cubic meter of water is about 1000 kg, or 1000*9.8 = 9800 Newton so the pressure in the bottom of the tank is 9.8 k-pa

mass of 1 cubic meter of Hg is 13600 kg, or 13600*9.8 or 133.28 kN
for a pressue of 133.28 Pa

This pressure difference causes mercury to flow into the water tank until pressures are equalized, with a height in the water tank h

Total mass = 13600 + 1000 = 14600 kg, or weight of 143080 Newtons
this will equalize between the two containers at 71540 N or 7300 kg in each side.

the 7300 kg will consist of 1000 kg of water with a height of 1 meter, and 6300 kg of mercury. 6300 kg / 13600 kg/m³ = 0.4632 m³ of Hg.

So, the water tank will have 1 meter of water and 0.4632 meter of Hg, total 1.4632 meter.