Question

B. Using the five steps from the online notes, conduct a randomization test given that 90 students in a random sample of 150 use the eTextbook. Be sure to include your relevant StatKey output.

Step 1: Determine what type of test you need to conduct and write the hypotheses.

Step 2: Use StatKey to construct a randomization distribution under the assumption that the null hypothesis is true. Take at least 5000 resamples.

Step 3: Use the randomization distribution to find the p-value. Include a screenshot of your distribution with the p value in red and write a statement identifying your p value.

Step 4: Decide if you should reject or fail to reject the null hypothesis.

Step 5: State a real-world conclusion in relation to the original research question

Answer 1

Step 1: Test for Single Proportion is used for the given data

since 90 students in a random sample of 150 use the eTextbook i.e. n = 150, x = 90

Step 2: H0: The proportion of the student who use the eText books is 50%

i.e. H0: P = 0.50

H1: The proportion of the student who use the eText books is not 50%

i.e. H1: P not = 0.50

Step 3: We generate the 10,000 random samples from randomization test for a proportion, the Output from Statkey is

StatKe Randomization Test for a Proportion Custom Data Edit Data Generate 1000 Samples Generate 1 Sam ple Generate 10 Sam ples Generate 100 Samples Reset Plot Null hypothesis: p0.s Randomization Dotplot of Proportion 700 Original Sample samples-10000 Left Tail Two-TailRight Tail mean 0.500 Sample Size Proportion Count std. error 0.041 600 90 150 0.600 Randomization Sample 500 Sample Size Proportion Count 400 76 150 .507 0.031 0.031 0.937 300 200 100 0.65 0.40 0.45 0.55 0.60 null- 0.5 0.420 0.580

P-value = 0.031+0.031 = 0.061

Step 4: Since P-value > alpha 0.05 so we accept H0

Step 5: Thus we conclude that the proportion of the student who use the eText books is 50%