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2. (5 pt) Assume that the two samples are independent simple random samples selected from normally distributed populations and do not assume that the population standard deviations are equal. a) Test the claim using the P-value method or critical value method b) Construct a confidence interval suitable for testing the following claim The following statistics are listed for IQ scores for a random sample of subjects with high levels and low levels of lead in their blood. Use a 0.05 significance level to test the claim that the mean IQ score of people with low levels is higher than the mean IQ score of people with high levels. Low Lead Level: n = 78 X = 92.88462 s = 15.34451 High Lead Level: n = 21 * = 86.90476 S = 8.988352

Answer 1

Let, lou lead level : n,=78, % =92.88962, &13 15.34451 High Leed Level :En, = 21, Xg = 86.90436,82=8.98835 S where uis l2aneipopln. vls H, : Mi>l2. Ho: Mi=42 Teststauahe mean 1a Scores Low lead leuel tnitn-2 Wigh Lead Level respedticy?. +32 8,2 92.88462 - 86.90476 f15-34451)2+(8.988352 2.282 pvelue = p(t> 2. 282) : Sincepunelue< x O.o13 wheu d =ono5- we rojeck ho ß Conclude thet is I Q scores ol Cow levels mean meen I Q Seored of peoplewith highlevel than Wigher b) 957. Confidence inteuvel fet u1-llg is :- T-Ts I tag Initn2=2). B,?+822 92.8 BNG2 -86.9o 476 7 toios (78+21-2) x (15-344sIy +8.988.32) 구s 5.979867 1.661 x 2.6202 1.6 277 l0.3320)