x1 = 91, x2 = 88.452, s1 = 10.354, s2 = 10.064, n1 = n2 = 11
H0: µ1 = µ2
H1: µ1 > µ2
Test statistic =
[(x1 - x2)-(µ1-µ2)] / [((s12(n1-1) + s22(n2-1))/(n1+n2-2))^0.5*(1/n1+1/n2)^0.5] |
= ((91-88.452)-0)/((((10.354*10.354*10)+(10.064*10.064*11))/(11+11-2))^0.5*(1/11+1/11)^0.5)
= 0.57
Degrees of freedom: df = n1+n2-2 = 11+11-2 = 20
p-value (Using Excel function T.DIST.RT(test statistic, df)) = T.DIST.RT(0.57,20) = 0.288
Do not reject H0, insufficient evidence.
Assume that the samples independent simple random samples selected from normally distributed populations. Do not assume...
help 2. (5 pt) Assume that the two samples are independent simple random samples selected from normally distributed populations and do not assume that the population standard deviations are equal. a) Test the claim using the P-value method or critical value method b) Construct a confidence interval suitable for testing the following claim The following statistics are listed for IQ scores for a random sample of subjects with high levels and low levels of lead in their blood. Use a...
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Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both...
Medium lead level: 72,98,92,85,82,97,83,92,102,111,91 & high lead level: n2=11 , x2=90.267 , s2=10.588 %) 9.2.12-T EQuestion Help Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population...
Calculate the test statistic. Calculate the P-value. Construct a confidence interval. Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts...
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I need help. D AANBUentG Google G Google (2 jimin is a frealky bi G Untitled document My C Estimate Difference 2 Means () 01e Listed in the data table are IQ scores for a random sample of subjects with r from simple random samples selected from normally distributed populations Do not assume that the equal. medium lead ievels in their blood. Also listed are statistics a study done of IQ scores for a random sample of subjects with high...
A data set lists full IQ scores for a random sample of subjects with low lead levels in their blood and another random sample of subjects with high lead levels in their blood. The statistics are summarized below. Use a 0.05 significance level to test the claim that the mean IQ score of people with low lead levels is higher than the mean IQ score of people with high lead levels. Low Blood Lead Level: n = 77 x =...
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H0: H1: Calculate the t statistic. Calculate the P-value Construct a confidence interval. Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal....