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if (a > 0)   if (b < 0)      x = x + 5;   else      if (a...

if (a > 0)

  if (b < 0)

     x = x + 5;

  else

     if (a > 5)

        x = x + 4;

     else

        x = x + 3;

else

  x = x + 2;

Refer to Code Segment Ch 05-1. If x is currently 0, a = 0 and b = -5, what will x become after the statement shown is executed?

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Answer #1

If currently x=0 , a=0 and b= -5 , then the above code segment will give the value of x =2 after execution.

Since , a=0 and b=-5, the if condition (a>0) , (b<0) or (a>5) do not imply , therefore x=2 .

#include <stdio.h〉 int main() int a-e,b--5,x-0 if(a > 0) if (b<e) x=x+5; else if (a 〉 5) 1 else else printf x%d , x); return e;

Output:

find the execution of code segment below :

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