RSA algorithm is an assymetric cryptographic algirithm which used to encrypt and decrypt messages.Assymetric means it involves two keys, public key and private key, as one of the keys can be given to anyone and the other key will be private.
Here p and q are two prime numbers and given as p=23, q=17
> First, we need to find n, which is the product of p and q.
n = p x q
n = 23 x 17
n = 391
> After that compute Φ = (p-1)(q-1)
Φ = (23-1)(17-1) = 22 x 16
Φ = 352
> Public key value is given in the question, e = 3.
> Next is to find the private key d, so d is the inverse of e mod Φ = 1
i.e., de mod Φ = 1
d = e-1 mod Φ
Here Φ is 352, 352k+1 = 353, 705, 1057, 1409 where k=1,2,3,4...
Now check among those values which one is divisible by 3(public key), 705/3 = 235
705 is exactly divisible by 3, and d = 235
> So the two keys are {e,Φ} and {d, n}
key 1 = {3, 352} and key 2 = {235, 391} used for encryption and decryption respectively.
> Here asked to find the plain text from cipher text which is decryption.
To find decryption, t = cd mod n (where c is cipher text, d is private key)
Given c = 165 , we found d = 235 and n = 391
Plain text, t = 165235 mod 391
The same is handwritten and attached that image, can go through which is comfortable to you either typed or handwritten.
CIPHER THAT LETS LOOK PA RSA AT USES Two PRIMES p=23 AND q=17 PUBLIC KEY e=3...
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