f)
Refer value in the last row and s3 column, the value is 2, it is the shadow price of third constraint
Feasibility range of third constraint is: 4-4/1=0 and 4+2/1=6
Given change from 4 to 6 is within the feasibility range
Therefore, shadow price is applicable
Change in objective function value = Shadow price * change in value of b3
= 2*(6-4) = 4
New Objective value = old objective value + change
= 8 +4
= 12
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g)
The range of values of 4(b3) such that the values of x,y remain optimal is: 0 <= b3 <= 6
as determine in part f
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h)
The current slope of iso-profit line is = -c1/c2
= -2/1
= 2
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i)
Optimal range of 2(c1) is: 2-1/1=1 and 2+1/0=infinity
The range of values of 2(c1) such that the values of x,y remain optimal is: 1 <= c1 <= infinity
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